PHP :: Bug #50493 :: Terminator and Variable

Bug #50493	Terminator and Variable
Submitted:	2009-12-16 14:12 UTC	Modified:	2009-12-16 15:00 UTC
From:	v dot srinath dot php at gmail dot com	Assigned:
Status:	Not a bug	Package:	*General Issues
PHP Version:	5.2.11	OS:	Windows
Private report:	No	CVE-ID:	None

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[2009-12-16 14:12 UTC] v dot srinath dot php at gmail dot com

Description:
------------
<?php
s
?>
output: nothing appears on browser.
<?php echo $row['column'];s?> 
doesn't show any error.
Is this code acceptable in php?

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[2009-12-16 14:21 UTC] jani@php.net

Yes, you get a notice. You just don't have notices enabled in your error_reporting setting. RTFM.

[2009-12-16 15:00 UTC] v dot srinath dot php at gmail dot com

thanks.I am Newbie to PHP.

I turned on the error reporting engine and now I got the 'notice' reports. Here I assumed "s" as variable but it doesn't show any error.
So how "s" is considered here?

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