Description:
------------
Calling a php bug1B.php via exec gives invalid 0 as return code, when 
picking up 1 from caller when caller is PHP script. You call bug1A.php 
from a terminal. - ./bug1A.php

Script bugA1.php invokes bug1B.php via exec() with parameter '1', which 
script bug1B.php picks up. It looks like all digits are converted to 0 
(zero) if you do not explicit cast $argv[1] to integer.

When you call bug1B from a shell script it works like expected, 
returning 1 as return code.



Reproduce code:
---------------
#!/home/tooljn/PHP5.3/local/bin/php
<?php
//this is the caller - bug1A.php	
$lastOutputLine = exec("./bug1B.php 1", $output, $sysRC);
print "return code from bug1B.php rc=$sysRC\n";
?>

#!/home/tooljn/PHP5.3/local/bin/php
<?php
//this is the called - bug1B.php
// If we take away cast (int) string "1" is converted to integer 0 (zero), when called from bug1A.php
//if ($argc == 2 and ($argv[1] == '0' or $argv[1] == '1')) $rc = (int) $argv[1];
if ($argc == 2 and ($argv[1] == '0' or $argv[1] == '1')) $rc = $argv[1];
print "bug1B.php rc=$rc\n";
exit($rc);
?>

Expected result:
----------------
return code from bug1B.php rc=1;



Actual result:
--------------
return code from bug1B.php rc=0;