Description:
------------
The example prints 9 as the value of $a , though it should be 8;
The fact the referencing $a[0] causes $a[0] to become a reference itself , is dangerous in cases like this where it is possible to change the value of $a[0] though it was not originally defined as a reference.





Reproduce code:
---------------
function a($c){
  $c[0] = 9;
}

$a[0] = 8;

$c = &$a[0];
a($a);
echo $a[0];

Expected result:
----------------
The value of $a should be 8

Actual result:
--------------
The value printed is 9