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Bug #46208 Comparing integer to string loses leading 0's
Submitted: 2008-10-01 06:19 UTC Modified: 2008-10-02 09:51 UTC
From: brennan at reverseproductions dot com Assigned:
Status: Not a bug Package: Scripting Engine problem
PHP Version: 5.2.6 OS: OSX
Private report: No CVE-ID: None
View Developer Edit
 [2008-10-01 06:19 UTC] brennan at reverseproductions dot com 
Description:
------------
When comparing an integer with a string any leading 0's in the integers 
are ignored. 






Reproduce code:
---------------
$day = "05";
echo "05 == 05: ";
if (!(strcmp(05, $day)))
 echo "equal";
else
 echo "not equal";

 echo "<br>"; 
 
echo "07 == 05: "; 
if (!(strcmp(07, $day)))
 echo  "equal";
else
 echo "not equal";

Expected result:
----------------
05 == 05: equal
07 == 05: not equal

Actual result:
--------------
05 == 05: not equal
07 == 05: not equal

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 [2008-10-01 09:20 UTC] tularis@php.net 
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

05 is an integer, not a string. And as far as integers go, 5 === 05 === 000000005. If you want it to be a string, declare it as a string: '05'.
 [2008-10-02 03:01 UTC] brennan at reverseproductions dot com 
The issue is that the PHP language parser does seem to allow for 
comparing integers with strings.  As an example evaluate 5 == "5".  
Because of this, I would expect the integers, when automatically 
converted to a string, to be converted in a way which leaves the leading 
zeroes.  To reword: when PHP converts 05 to a string behind the scenes 
to evaluate 05 == "05" it should leave the leading 0's.

Maybe this ticket would be better marked as enhancement?
 [2008-10-02 09:51 UTC] scottmac@php.net 
Integers prefixed with 0 are octal numbers, so 05 is really 5.

011 == 9

It's working exactly as designed.
 
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