Description:
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if the haystack array has an "int 0" in the array and the needle does not exists, true is returned. This is only the case in none strict setting, but it is still a bug.

Please do not close this as bogus and refer to the documentation and the strict flag. The flag works as can be seen with the "string 0" in the search part.

But it is wrong to return true if complete different character (char f) is searched and it returns true for "int 0"

Reproduce code:
---------------
$char = array('a', 'f', '0');
$array_search_data = array ('a', 'b', 'c', 0, '0');
print "Valid: ".print_r($array_search_data, 1)."<br>";
print "<br>";
foreach ($char as $_char)
{
        print "I[$_char] (false): in array: ".in_array($_char, $array_search_data)." | array search: ".array_search($_char, $array_search_data)."<br>";
        print "I[$_char] (true): in array: ".in_array($_char, $array_search_data, true)." | array search: ".array_search($_char, $array_search_data, true)."<br>";
        print "<br>";                                                                                                                                 }

Expected result:
----------------
in_array should return false for the search of 'f' and not true or the position of "int 0" in the array.

Actual result:
--------------
in_array (and also array_search) return true (or the position of "int 0" if a needle cannot be found in the array.