Description:
------------
Given the following example:

<?php
function Test()
{
    static $a = 0;
    echo $a;
    $a++;
}
?>


I reckon the explanation is lacking one important point: the fact that 
the static variable line is executed only on the first call to the 
function (at least this is what emerged in a discussion I had with 
some of you in the mailing list).
I think this point should be clearly stated because beginners may not 
know how this works in C or other languages.

At the moment the exlanation reads:

This function is quite useless since every time it is called it sets 
$a to 0 and prints "0". The $a++ which increments the variable serves 
no purpose since as soon as the function exits the $a variable 
disappears. To make a useful counting function which will not lose 
track of the current count, the $a variable is declared static:
Now, every time the Test() function is called it will print the value 
of $a and increment it.

A non-expert could easily think that this variable gets set to zero on 
each call to the function.