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[2007-12-18 14:36 UTC] csaba at alum dot mit dot edu
Description: ------------ This continues bug report 43572 at http://bugs.php.net/bug.php?id=43572&edit=2 which discussion is incomplete, yet has been prematurely closed. > The value that you expect (0) is obtained using float precision. > (In C) PHP uses double, and with this type fmod() returns 1.3. So, to be concrete: $a = 6.5; print gettype($a); // double $b = 1.3; print gettype($b); // double $c = $a / $b; print gettype($c); // double $d = 5.0; print gettype ($d); // double print $c - $d; // 0 print (gettype($c - $d)); // double print ($c===$d) ? "same" : "different"; // same print gettype ($b - fmod($a, $b)); // double print $b - fmod($a, $b); // 2.22044604925E-16 In other words, PHP's own (double) math shows that 6.5 / 1.3 === 5.0 Regardless of the internal representation and precision of 6.5 and 1.3, division of the former ($a) by the latter ($b) results in a double value identical to 5.0. fMod should return 0 in this situation. Csaba Gabor from New York PS. I would prefer that these comments be moved to bug 43572 and that it be reopened until the discussion is completed, rather than having multiple threads. PatchesPull RequestsHistoryAllCommentsChangesGit/SVN commits
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C code: --- float a = 6.5, b = 1.3; double c = 6.5, d = 1.3; puts("Float:"); printf("%f\n", fmod(a, b)); printf("%f\n", a / b); printf("%f\n", b - fmod(a, b)); puts("Double:"); printf("%G\n", fmod(c, d)); printf("%G\n", c / d); printf("%G\n", d - fmod(c, d)); --- Result: Float: 0.000000 5.000000 1.300000 Double: 1.3 5 2.22045E-16