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Doc Bug #37913 preg_match_all typo
Submitted: 2006-06-26 08:16 UTC Modified: 2006-06-26 10:35 UTC
From: tom at foreignproperty dot com Assigned:
Status: Not a bug Package: Documentation problem
PHP Version: Irrelevant OS:
Private report: No CVE-ID: None
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 [2006-06-26 08:16 UTC] tom at foreignproperty dot com 
Description:
------------
In the description for preg_match_all, in the 2nd example, Find matching HTML tags (greedy), the part 2 and part 3 array values are wrong ($matches[3], $matches[4]).

  echo "matched: " . $matches[0][$i] . "\n";
  echo "part 1: " . $matches[1][$i] . "\n";
>>  echo "part 2: " . $matches[3][$i] . "\n";       <<
>>  echo "part 3: " . $matches[4][$i] . "\n\n";     <<

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 [2006-06-26 08:40 UTC] takagi@php.net 
No, that's perfectly correct.

The regx is "/(<([\w]+)[^>]*>)(.*)(<\/\\2>)/".

So,
[1] correspond to (<([\w]+)[^>]*>),
[2] correspond to ([\w]+),
[3] correspond to (.*), and
[4] correspond to (<\/\\2>).
 [2006-06-26 09:30 UTC] tom at foreignproperty dot com 
look at the array keys.
it goes $matches[0], $matches[1], then jumps to $matches[3] and $matches[4]

Shouldn't part 2 be matches[2], and part 3 be $matches[3]?
 [2006-06-26 10:35 UTC] nlopess@php.net 
No. The example is correct. It shows how to use nested parenteses and backreferences.
 
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