Would you expect this to work different somehow?

<?php

printfoobar();
exit;

$FOO = 'bar');

function printfoobar()
{
    echo $GLOBALS["FOO"];
}

?>   

I would not.  Not only did you call the function before the define, but you exit() before the define.  There is no way that is getting defined.

same happens w/o the exit too. 

anyway... of course I expect a different result in that case. It's very confusing for (e.g.) c programmers where that works just fine:


int main(void)
{
   printfoobar();

   return 0;
}


#define FOO "bar"

void printfoobar()
{
   printf(FOO);
}


So it should be documented IMHO... a small extra sentence in the documentation doesn't hurt.. I think ;)

This bug has been fixed in the documentation's XML sources. Since the
online and downloadable versions of the documentation need some time
to get updated, we would like to ask you to be a bit patient.

Thank you for the report, and for helping us make our documentation better.

I believe it can't hurt anybody.

http://patches.colder.ch/constants-1.43.patch?markup

I reopen this bug as a consequence of Sean's comment (thanks for it).

Will fix that ASAP.

This bug has been fixed in the documentation's XML sources. Since the
online and downloadable versions of the documentation need some time
to get updated, we would like to ask you to be a bit patient.

Thank you for the report, and for helping us make our documentation better.

Moved from language/constants to define()'s manual page.

I hope it's alright now (: