Description:
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Hi,

I've a xampp installation, in WinXP, with:
Apache 2 
PHP 5.1.4

php.ini settings:
java.class.path = "C:\Program Files\xampp\php\java\php_java.jar"
java.home = "C:\Program Files\Java\j2re1.4.2_03"
;java.library = "C:\Program Files\Java\j2re1.4.2_03\bin\client\jvm.dll"
java.library = "C:\Program Files\Java\j2re1.4.2_03\bin\server\jvm.dll"
java.library.path = "C:\Program Files\xampp\php\ext"

When a execute the script listed I get a Apache.exe error, "access violation" kind of error.

Can anyone help me, please!

Thanks in advance!


Reproduce code:
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<?
  $system = new Java("java.lang.System");
  print "Java version=".$system->getProperty("java.version")." <br>\n";
  print "Java vendor=".$system->getProperty("java.vendor")." <p>\n\n";
  print "OS=".$system->getProperty("os.name")." ".$system->getProperty("os.version")." on ".$system->getProperty("os.arch")." <br>\n";

  $formatter = new Java("java.text.SimpleDateFormat","EEEE, MMMM dd, yyyy 'at' h:mm:ss a zzzz");
  print $formatter->format(new Java("java.util.Date"))."\n";
?>