Description:
------------
In the manual page describing each() function is the following caution:
"Because assigning an array to another variable resets the original arrays pointer, ..."

I think that this is a bug, although it is documented and treated as feature.
I realized that the pointer is reset when a copy of an  array is made. However, PHP makes some optimizations which prevents unnecessary array copying (which is good feature).
Since these optimizations are not known for users (and shouldn't be) the behavior of inner pointer is thus non-deterministic from user's point of view.

See the follwoing code. 
Its output depends on whether the statement $b[] = 1; is commented or not.


Reproduce code:
---------------
function f($a) { $b = $a; /*$b[] = 1;*/ return $b; }

$arrayOuter = array("key1","key2");
$arrayInner = array("0","1");

while(list(,$o) = each($arrayOuter))
{
        $q = f($arrayInner);
	while(list(,$i) = each($arrayInner)) 
        {
		print "inloop $i for $o\n";
	}
}



Expected result:
----------------
inloop 0 for key1
inloop 1 for key1

Actual result:
--------------
inloop 0 for key1
inloop 1 for key1
inloop 0 for key2
inloop 1 for key2