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Bug #27623 implementation of interfaces not correct handled
Submitted: 2004-03-17 05:46 UTC Modified: 2004-03-17 13:13 UTC
Votes:1
Avg. Score:5.0 ± 0.0
Reproduced:1 of 1 (100.0%)
Same Version:1 (100.0%)
Same OS:1 (100.0%)
From: fd@php.net Assigned:
Status: Not a bug Package: Class/Object related
PHP Version: 5CVS-2004-03-17 (dev) OS: debian linux
Private report: No CVE-ID: None
View Developer Edit
 [2004-03-17 05:46 UTC] fd@php.net 
Description:
------------
A implementation of a class whith a method which is not declared as in the interface should throw an error, which it does in php5b4 but not in the current HEAD.

Reproduce code:
---------------
<?php

    interface Person {
        function doSth($sWhat,$sWhere);
    }
     
    class Member implements Person {
        function doSth($sWhat) {
            echo "Person does ".$sWhat."\n";
        }
    }
    
    $Member = new Member;
    $Member->doSth('nothing');

?> 

Expected result:
----------------
Fatal error: Declaration of Member::doSth() must be the same as Person::doSth()

Actual result:
--------------
Person does nothing

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 [2004-03-17 05:53 UTC] derick@php.net 
This is correct behavior now, turn on E_STRICT and E_ALL and you'll see it.
 [2004-03-17 06:04 UTC] fd@php.net 
Actually I do not get the point why that does not throw a fatal error, in my opinion the script should terminate on such an error, shouldn't it?
 [2004-03-17 06:27 UTC] derick@php.net 
No, we had a discussion on this on the internals@ list. This only throws an E_STRICT type error.
 [2004-03-17 07:56 UTC] fd@php.net 
That does not make sence in my eys. As an example, if you have a interface "car" which declares "four wheels" and an implementation of "car" just declares "three wheels" the car shouldn't even start driving. But now it does, I think that is stupid.
 [2004-03-17 13:13 UTC] helly@php.net 
Maybe it is but PHP is still a weak typed language and other people make good use of that fact. They have E_STRICT off because turning it on makes PHP a bit more type strict.
 
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