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[2003-10-10 15:04 UTC] pennington at rhodes dot edu
Description:
------------
I am querying an Active Directory server with PHP via LDAP to retrieve all of a particular user's attributes. All of that user's attributes in the LDAP directory are placed in a multi-dimensional array that I can query for a particular attribute I am interested in and return all of those values from the array by looping through that part of the array, using the correct key value.
So, in other words, I am using PHP's LDAP to grab all information about a user in Active Directory and put it into a single, multi-dimensional array called $info. This array has three levels of keys, such that:
$info[0][description][0]
would equal
Staff
because that is what is set up for the description attribute for a person in Active Directory. I am then looping through the entire array looking for values set with certain keys that I am interested in, which could be holding data in any order.
The problem occurs when I loop through the multi-dimensional array for attributes that share the second key, such as:
$info[0][memberof]
Because several different memberof attributes can be stored for a person in Active Directory, the LDAP-built array has values like:
$info[0][memberof][0] = Domain Admin
$info[0][memberof][1] = Finance User
$info[0][memberof][2] = Local Admin
and so on. If I count the number of member attributes that are actually in the LDAP server, I get a particular value, say 15. When I loop through these attributes in the array and count them up, I also get that same number. However, when I try to report back all of these attributes by printing them out, only 14 appear.
In other words, while the correct number of attributes are put into the array by PHP using LDAP, one of the keys in the array has no data associated with it (and should have data associated with it). This holds true for any LDAP-created array where an LDAP attribute has more than one value associated with it. All of those values are reported back to the PHP via LDAP and keys are created in the array for all of those values, but strangely one (and only one) of the data values will disappear if a certain attribute has more than one value associated with it.
Reproduce code:
---------------
Here is the code I'm using to build the troubled array via PHP's LDAP. Of course, you have to authenticate to our LDAP server to do the test on a particular user, so I am not able to point to a place on the web to demonstrate this.
<?php
if ($name_submitted != "" && $passwd_submitted != "") {
$ldap_host = "ldap://someserver.rhodes.edu";
$base_dn = "CN=Users,DC=rhodes, DC=edu";
if ($search_submitted == "") {
$search_value = $name_submitted;
} else {
$search_value = $search_submitted;
}
$filter = "(CN=$search_value)";
$ldap_user = "CN=$name_submitted, CN=Users, DC=rhodes, DC=edu";
$ldap_pass = $passwd_submitted;
$connect = ldap_connect( $ldap_host, $ldap_port)
or exit("Could not connect to LDAP server");
// required to search AD, according to note in PHP manual notes
ldap_set_option($connect, LDAP_OPT_PROTOCOL_VERSION, 3);
ldap_set_option($connect, LDAP_OPT_REFERRALS, 0);
$bind = ldap_bind($connect, $ldap_user, $ldap_pass)
or exit("Could not bind to $ldap_host");
echo "Successful bind to $ldap_host with $bind<br><br>\n";
$read = ldap_search($connect, $base_dn, $filter)
or exit("Unable to search ldap server");
$info = ldap_get_entries($connect, $read);
echo $info["count"]." entries returned for $filter<br><br>\n";
$ii=0;
for ($i=0; $ii<$info[$i]["count"]; $ii++){
$data = $info[$i][$ii];
if ($data == "memberof") {
$total_memberof = (count($info[$i][$data]));
echo "Total memberof entries returned: $total_memberof<br><br>\n";
$total = 0;
$total = count($info[$i][$data]);
$jj=0;
for ($jj=0; $jj<$total; $jj++) {
if ($info[$i][$data][$jj] == "CN=STAFF,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu") {
echo "<b>Got Staff Match</b> ";
$user_type = "staff";
} elseif (($info[$i][$data][$jj] == "CN=FACULTY,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu") && $user_type == "") {
echo "<b>Got Faculty Match</b> ";
$user_type = "faculty";
} elseif (($info[$i][$data][$jj] == "CN=Students,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu") && $user_type == "") {
echo "<b>Got Students Match</b> ";
$user_type = "student";
}
echo $i." ".$ii." ".$jj." ".$data.": ".$info[$i][$data][$jj]."<br>\n";
}
}
}
ldap_unbind($connect);
echo "<br><br><b>User Type is: ";
switch ($user_type) {
case "staff":
echo "STAFF";
break;
case "faculty":
echo "FACULTY";
break;
case "student":
echo "STUDENT";
break;
default:
echo "UNKNOWN";
break;
}
echo "</b><br><br>\n";
echo "<br><br><a href=\"index.php\">Search again</a><br><br>\n";
} else {
echo "<html><head></head><body>\n";
echo "<form action=\"index.php\" method=\"POST\">\n";
echo "AD User Name: <input type=\"text\" name=\"name_submitted\"><br>\n";
echo "AD Password: <input type=\"password\" name=\"passwd_submitted\"><br>\n";
echo "Search User Name: <input type=\"text\" name=\"search_submitted\"><br>\n";
echo "<input type=\"submit\" value=\"Submit\">\n";
echo "</form>\n";
echo "</body></html>\n";
}
?>
Expected result:
----------------
Total memberof entries returned: 13
0 1 0 memberof: CN=STAFF_DL,OU=Distribution Lists,OU=Groups,DC=rhodes,DC=edu
0 1 1 memberof: CN=Planning,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu
0 1 2 memberof: CN=FACSTAFF,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu
0 1 3 memberof: CN=Council,OU=Distribution Lists,OU=Groups,DC=rhodes,DC=edu
0 1 4 memberof: CN=PRESIDENT,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu
0 1 5 memberof: CN=FACTBOOK,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu
0 1 6 memberof: CN=INFO_SERVICES,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu
0 1 7 memberof: CN=CABINET,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu
0 1 8 memberof: CN=Senior2006,OU=Distribution Lists,OU=Groups,DC=rhodes,DC=edu
0 1 9 memberof: CN=NT Users,CN=Users,DC=rhodes,DC=edu
0 1 10 memberof: CN=NTSETUP,CN=Users,DC=rhodes,DC=edu
0 1 11 memberof: CN=Domain Users,CN=Users,DC=rhodes,DC=edu
0 1 12 memberof: CN=STAFF,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu
Actual result:
--------------
Total memberof entries returned: 13
0 1 0 memberof: CN=STAFF_DL,OU=Distribution Lists,OU=Groups,DC=rhodes,DC=edu
0 1 1 memberof: CN=Planning,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu
0 1 2 memberof: CN=FACSTAFF,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu
0 1 3 memberof: CN=Council,OU=Distribution Lists,OU=Groups,DC=rhodes,DC=edu
0 1 4 memberof: CN=PRESIDENT,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu
0 1 5 memberof: CN=FACTBOOK,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu
0 1 6 memberof: CN=INFO_SERVICES,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu
0 1 7 memberof: CN=CABINET,OU=Security Groups,OU=Groups,DC=rhodes,DC=edu
0 1 8 memberof: CN=Senior2006,OU=Distribution Lists,OU=Groups,DC=rhodes,DC=edu
0 1 9 memberof: CN=NT Users,CN=Users,DC=rhodes,DC=edu
0 1 10 memberof: CN=NTSETUP,CN=Users,DC=rhodes,DC=edu
0 1 11 memberof: CN=Domain Users,CN=Users,DC=rhodes,DC=edu
0 1 12 memberof:
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Last updated: Mon Oct 27 16:00:01 2025 UTC |
It appears that ldapsearch at that URL is not compiled with Kerberos support, which may be required to search Active Directory LDAP servers. I'm still doing research, however... D:\openldap\bin>ldapsearch -LLL -H ldap://someserver.rhodes.edu -P 3 -D pennington -k ldapsearch: not compiled with Kerberos support I tried it with just SASL and that wasn't appreciated either: D:\openldap\bin>ldapsearch -LLL -H ldap://someserver.rhodes.edu -P 3 -D pennington -I ldap_sasl_interactive_bind_s: Unknown authentication method (86) additional info: SASL(-4): no mechanism available: Unable to find a call back: 2 Can anyone verify that Kerberos support is required to search Active Directory LDAP servers? Is anyone using the OpenLDAP ldapsearch program to search Active Directory LDAP servers? If so, what kind of command should I use to get ldapsearch to search Active Directory? I am using "CN=Users,DC=rhodes,DC=edu" for the Base DN, "CN=_search_value_" for the name to search for, and to bind to the Active Directory LDAP server, you have to use this string as the username: "CN=_authorized_user_,CN=Users,DC=rhodes,DC=edu"