Description:
------------
call_user_func and call_user_func do respect functions that return references.  That is, function foo that returns a references to an object, does not return a reference to an object when foo is called via call_user_func.  Instead, foo called via call_user_func returns a "copy" of the object.  (I'm not sure "copy" is the right word.)  See the code example for a concise example of the problem.

Note: this may cease to be a problem in PHP5, as it is my understanding that objects will be passed/returned by reference by default.

If my you do not understand my description and my reproduce code, email me and I will happily explain it to you.

Many thanks.

Reproduce code:
---------------
<?php

$x->var = 1;

function & foo (&$x) {
  return $x; }

$y =& foo ($x);
print "y->var = ". $y->var. "    <br>\n";
$x->var++;
print "y->var = ". $y->var. "    <br>\n";

$z =& call_user_func ("foo", &$x);
print "z->var = ". $z->var. "    <br>\n";
$x->var++;
print "z->var = ". $z->var. "    <br>\n";

$w =& call_user_func_array ("foo", array (&$x));
print "w->var = ". $w->var. "    <br>\n";
$x->var++;
print "w->var = ". $w->var. "    <br>\n";

?>


Expected result:
----------------
y->var = 1    <br>
y->var = 2    <br>
z->var = 2    <br>
z->var = 3    <br>
w->var = 3    <br>
w->var = 4    <br>

Note that I expect z->var and w->var to get inceremented just as y->var gets inceremented.

Actual result:
--------------
y->var = 1    <br>
y->var = 2    <br>
z->var = 2    <br>
z->var = 2    <br>
w->var = 3    <br>
w->var = 3    <br>

Note that in reality, however, z->var and w-> did not get inceremented.