Description:
------------
See the reproduce code. I have a variable $ref, which is a reference to another variable. I am passing $ref to closure as use() by value, but, this kind of passing corrupts $ref variable after definition of closure and $ref becomes no longer reference, but points directly to copied data of $source variable, which $ref was previously referring to. However, if i define closure the following way:

$closure =function() use( &$ref) {// note pass-by-reference
  echo $ref;
};

the $ref does not loose it's state.

Reproduce code:
---------------
$source ='Dmitry';
$ref =&$source;

$closure =function() use( $ref) {
  echo $ref;
};

$ref ='Dmitry2';

echo $ref ."\n";
echo $source ."\n";

Expected result:
----------------
Dmitry2
Dmitry2

Actual result:
--------------
Dmitry2
Dmitry