Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

The assignment is executed before the "and" operator, see the precedence table in the docs, http://php.net/operator

sorry wrong URL, correct one: http://php.net/operators

Thank for your answer johannes@php.net but still I think someone is not correct, perhaps I am wrong.

I have read your link: http://es2.php.net/manual/en/language.operators.logical.php:

And y read there:
$a and $b => TRUE if both $a and $b are TRUE.

I had writed another simple code that dont run as expected (I send you at the end of this note).  The result that show on my computer is:
$l1 = TRUE, $l2 = FALSE => $l1 and $l2 is FALSE
$l1 = TRUE, $l2 = FALSE => $l1 and $l2 is TRUE
$l1 = TRUE, $l2 = FALSE => $l1 and $l2 is FALSE
$l1 = TRUE, $l2 = FALSE => $l1 and $l2 is FALSE

I think the second line must be as the another lines.  What is wrong?

Thanks for your attention,
jaz


This is the code:

<?php
$v1	= "A";
$v2	= 0;

$l1	= $v1=="A";
$l2	= $v2!=0;
$flag1 = $l1 and $l2;
$flag2 = ($l1 and $l2);
$flag3 = $l2 and $l1;

echo "\$l1 = ".showAstxt($l1).", \$l2 = ".showAstxt($l2)." =>  \$l1 and \$l2 is ".showAstxt($l1 and $l2)."<br>";
echo "\$l1 = ".showAstxt($l1).", \$l2 = ".showAstxt($l2)." =>  \$l1 and \$l2 is ".showAstxt($flag1)."<br>";
echo "\$l1 = ".showAstxt($l1).", \$l2 = ".showAstxt($l2)." =>  \$l1 and \$l2 is ".showAstxt($flag2)."<br>";
echo "\$l1 = ".showAstxt($l1).", \$l2 = ".showAstxt($l2)." =>  \$l1 and \$l2 is ".showAstxt($flag3)."<br>";

// ============================================================

function showAstxt($v)
{
	return $v ? "TRUE" : "FALSE";
}
?>

Please see the operator precedence table and explanation on the page I ahve given, somewhere in the upper area are "&&", "||" and so on, then "=" and in the bottom "and", "or", "xor" which means the assignment is done before the "and" operator is executed. For further questions please refer to other support forums, see http://php.net/support.php

Please take a look at the examples on php.net/operators.logical

Sorry by I still I think something is wrong.  Please take a while to see the next code (or run it on your machine):

<?php
$l1		= true;
$l2		= false;
$l1_and_l2	= $l1 and $l2;
$l2_and_l1	= $l2 and $l1;

echo "<pre>";
echo "Here l1 and l2 is: ";
var_dump($l1 and $l2);

echo "But here l1 and l2 is: ";
var_dump($l1_and_l2);

echo "And here l2 and l1 is: ";
var_dump($l2_and_l1);

echo "What happens?";
echo "</pre>";
?>

Te answer on my machine for the previous code is:

Here l1 and l2 is: bool(false)
But here l1 and l2 is: bool(true)
And here l2 and l1 is: bool(false)
What happens?

... And I think it must be false in all the three cases !!

Thanks in advance for your attention,
jaz

*Please* look at Example 1 at http://php.net/operators.logical, as requested by colder - this demonstrates your example exactly and shows that what you're getting is the expected result.  The operator precedence table at http://php.net/operators#language.operators.precedence (also previously referred to) may also help.

This is *not* a bug, so don't add to this conversation.  If you need further explanation, please ask in the support forums (such as php-general@lists.php.net).

Thanks, I was wrong (sorry for my insistence).  Assignement (=) is done before the and/or opperation but the &&/|| opperation is done before the assignement (=).

Thanks very much for your attention and explanation.