This example is more simple:

$test = new stdClass();
$Objeto = new stdClass();

$test->valor = "The first value";
$Objeto->valorDeTeste[] = $test;

$test->valor = "The second value";
print_r($Objeto->valorDeTeste);


Expected:
Array
(
    [0] => stdClass Object
        (
            [valor] => The first value
        )

)

Actual

Array
(
    [0] => stdClass Object
        (
            [valor] => The second value
        )

)

What does it output when you replace print_r() with var_dump() ?

"What does it output when you replace print_r() with var_dump() ?"

R: The same

That's impossible, the output of var_dump() differs a LOT from print_r(). So can you please really test it?

I'm sorry, 'The same' = 'The same problem'

CODE:
$test = new stdClass();
$Objeto = new stdClass();

$test->valor = "The first value";
$Objeto->valorDeTeste[] = $test;

$test->valor = "The second value";

echo "<pre>";
print_r($Objeto->valorDeTeste);
echo "<br />";
var_dump($Objeto->valorDeTeste);
echo "</pre>";








Array
(
    [0] => stdClass Object
        (
            [valor] => The second value
        )

)

array(1) {
  [0]=>
  object(stdClass)#1 (1) {
    ["valor"]=>
    string(16) "The second value"
  }
}

How is this weird?  $test is an object.  You store a reference to $test, 
and then you modify $test.  Since you only stored a reference to the 
original object, of course you will see the new value when you print out 
the reference.

This changed between PHP4 and PHP5.  PHP4 stores a copy rather than a 
reference.  If you are looking for the PHP4 behavior, you can use the 
"clone" keyword.  e.g. $Objeto->valorDeTeste[] = clone $test;

Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php