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Bug #35699 date() can't handle leap years before 1970
Submitted: 2005-12-16 06:11 UTC Modified: 2005-12-20 17:01 UTC
From: iquito at gmx dot net Assigned: derick (profile)
Status: Closed Package: Date/time related
PHP Version: 5.1.1 OS: Debian Sarge
Private report: No CVE-ID: None
View Developer Edit
 [2005-12-16 06:11 UTC] iquito at gmx dot net 
Description:
------------
strtotime() doesn't seem to handle leap years before 1970 correctly, all dates in a leap year are off by one day when converted by strtotime().

Reproduce code:
---------------
/* shows 1964-06-07 instead of 1964-06-06 */

echo date('Y-m-d', strtotime('1964-06-06'));

/* shows the correct date, 1963-06-06, thus confirming that it has something to do with leap years, non-leap-years aren't affected. */

echo date('Y-m-d', strtotime('1963-06-06'));

/* curiously, also dates in january and february of a leap year are affected by this bug */

echo date('Y-m-d', strtotime('1964-01-06')); // returns 1964-01-07

Expected result:
----------------
echo date('Y-m-d', strtotime('1964-06-06')); // should return 1964-06-06 !

Actual result:
--------------
echo date('Y-m-d', strtotime('1964-06-06')); // returns 1964-06-07 !

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 [2005-12-20 16:20 UTC] derick@php.net 
strtotime is actually corrrect here, it's the date() function that is broken:

<?php
date_default_timezone_set("UTC");
$utc_time1 = strtotime('1964-01-01 00:00:00 UTC');
$utc_time2 = strtotime('1963-12-31 00:00:00 UTC');
echo $utc_time1, ':', $utc_time2, " - ", $utc_time1 - $utc_time2, "\n";
echo date(DATE_ISO8601, $utc_time1), "\n";
echo date(DATE_ISO8601, $utc_time2), "\n";
?>

-189388800:-189475200 - 86400
1964-01-02T00:00:00+0000
1963-12-31T00:00:00+0000

compare timestamp with date program:
derick@kossu:~$ date +%s --date "1964-01-01 00:00:00 UTC"
-189388800
derick@kossu:~$ date +%s --date "1963-12-31 00:00:00 UTC"
-189475200
 [2005-12-20 17:01 UTC] derick@php.net 
This bug has been fixed in CVS.

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